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A contribution to IET@150

A factory substation, constructed in the 60s, still in active service is supplied at 11,000v, through an underground cable of 0.06 sq.in. section 7 miles from a substation containing 2 ---- 33,000/11,000v transformers each 2,500 kVA + 5% reactance. The short circuit kVA on the 33,000 busbars is 250,000 kVA.  What is the value of the short circuit at the factory substation?

Assuming a 5,000 kVA base, it is first necessary to find the equivalent reactance reactance of the supply system-----

5,000 x 100/React. % of supply system = 250.000kVA

React. of supply system = 5,000 x 100/250,000 = 2%

Each transformer on 5,000 kVA base has 5 x 5,000/2500 % reactance = 10%

2 in parallel give -------------------------------------------------------------------------------5%

As the resistance of the line will be comparable with its reactance, both should be taken into account.

Reactance of 0.06 sq.in. cable = 0.1682 ohms per mile.

Resistance of 0.06 sq.in. cable = 0.7184 ohms per mile.

Current equivalent to 5,000 kVA at 10,000v = 262 amps.

Voltage reactance drop = 262 x 0.1682 x 7= 308v

Voltage resistance drop = 262 x 0.7184 x 7 = 1,320v

Phase voltage =11,000/√3 = 6,350v

% Reactance drop = 308/6350 x 100 =4.85%

% Resistance drop = 1320x 100/6350 = 20.8%

Totalling up                       Resistance                          Reactance

Supply system                        ----                                        2.00%

Transformers                         ----                                        5.00%

Cable                                    20.8%                                     4.85%

                                              -----------------------------------------------

                                              20.8%                                     11.85%

% impedance = √20.8sq + 11.85sq  √432 + 140

= √572 = 23.9%

Short circuit = 5,000 x 100/23.9kVA = 20,900 kVA

Regards, UKPN. 

 

 

  • What is the relevance of this to BS7671? 

  • UKPN

    It is clearly a very old calculation, where does it come from? How does it relate to 150 years of the IEE/IET?

  • Each transformer on 5,000 kVA base has 5 x 5,000/2500 % reactance = 10%

    2 in parallel give -------------------------------------------------------------------------------2%

    Probably my being daft, but if one is 10% what's the calculation that gives two in parallel is 2%? (rather than perhaps 5%).

        - Andy.

  • I presume its an old exam question  or text book answer, was it an IEE publication or exam ?

    plenty would struggle that sum today too. Can't be that old in terms of 150 years - there is 33kv phase to phase voltage involved. 1900 to 1920s perhaps at the earliest

    By the 1930s we had the national grid at 132kV being rolled out, and pre about 1900 we had lots of private power stations near the areas they served,  HV  distribution was not a big thing until the 1890s

    according to wikepedia,

     London Electric Supply Corporation (LESCo) opened Deptford Power Station, UK's first (single-phase)  11kV AC power system, designed by Sebastian Ziani de Ferranti in 1891 and considered pretty state of the art at the time for using HV AC.

    Mike